2 X + 3 Y is equal to 7 and 6 X + 5 Y is equal to 11 solve by substitution
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2x+3y=7 - EQ no 1
6x+5y=11 - EQ no 2
solving 1 and 2
eq no 1×6= 12x+18y= 42
eq no 2×2=12x+10y=22
(-).
8y=20
y=20/8
y=2.5
substitute y=2.5 in eq no 1
2x+3y= 7
2x+3×2.5=7
2x+ 7.5=7
2x =7-7.5
2x= -0.5
x=-0.5/2
x=-0.25
therefore x=-0.25 and y= 2.5
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Answer:
x=8 and y=5/2
Step-by-step explanation:
2x+3y=7. (1)
6x+5y=11. (2)
from(1) =2x+3y=7
=2x=7-3y
=x=7-3y/2. (3)
therefore, substituting the value of x in eq 2 we get,
6(7-3y/2)+5y=11
6(7-3y)+10= 22
42-18y+10y=22
8y=22-42
y=20/8
y=5/2
for (3) we get
x=7-3(5/2)/2
x=7-15/2/2
x= 8
therefore x=8
and y=5/2
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