Question

(2) x - 3y = 1; 3x - 2y + 4 = 0

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Answer 1

x−3y=1

x−3y=1y= 3

x−3y=1y= 3x−1

x−3y=1y= 3x−1 ∣x=1,4,7∣

x−3y=1y= 3x−1 ∣x=1,4,7∣∣y=0,1,2∣

x−3y=1y= 3x−1 ∣x=1,4,7∣∣y=0,1,2∣3x−2y+4=0

x−3y=1y= 3x−1 ∣x=1,4,7∣∣y=0,1,2∣3x−2y+4=0y= 2

x−3y=1y= 3x−1 ∣x=1,4,7∣∣y=0,1,2∣3x−2y+4=0y= 23x+4

x−3y=1y= 3x−1 ∣x=1,4,7∣∣y=0,1,2∣3x−2y+4=0y= 23x+4 ∣x=0,2,4∣

x−3y=1y= 3x−1 ∣x=1,4,7∣∣y=0,1,2∣3x−2y+4=0y= 23x+4 ∣x=0,2,4∣∣y=2,5,8∣

Answer 2

Answer:

x=2 and y=3

Step-by-step explanation:

in first equation,

3x-2y=0

2x+y=7

y=7-2x

3x-2(7-2x)=0

7x=14

:x=2

similarly,in second equation,

3(2)-2y=0

6-2y=0

2y=6

:y=3