Question

2 x ​ − 4 1 ​ (x− 3 1 ​ )= 6 1 ​ (x+1)+ 12 1 ​

Answer 1

Answer:

\begin{gathered} Given \: simple \: Equation: \\\frac{x}{2} - \frac{1}{4}\Big(x-\frac{1}{3}\Big) = \frac{1}{6}(x+1) + \frac{1}{12} \end{gathered}

GivensimpleEquation:

2

x

−

4

1

(x−

3

1

)=

6

1

(x+1)+

12

1

/* Multiplying each term by 12 , we get */

\implies \frac{12x}{2} - \frac{12}{4}\Big(x-\frac{1}{3}\Big) = \frac{12}{6}(x+1) + \frac{12}{12}⟹

2

12x

−

4

12

(x−

3

1

)=

6

12

(x+1)+

12

12

\implies 6x - 3\Big(x-\frac{1}{3}\Big) = 2(x+1)+1⟹6x−3(x−

3

1

)=2(x+1)+1

\implies 6x - 3x + 1 = 2x + 2 + 1⟹6x−3x+1=2x+2+1

\implies 3x + 1 = 2x + 3⟹3x+1=2x+3

\implies 3x - 2x = 3 - 1⟹3x−2x=3−1

\implies x = 2⟹x=2

Therefore.,

\red {Value \:of \:x }\green {= 2 }Valueofx=2

•••♪

Answer 2

Answer:

Step-by-step explanation:

Hope it helps you