2^(x+4)(4)^2=16^x find the value of x
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Step-by-step explanation:
2ˣ⁺⁴ * 4² = 16ˣ
=> 2ˣ⁺⁴ * (2²)² = (2⁴)ˣ
=> 2ˣ⁺⁴ * 2⁴ = 2⁴ˣ ( ∵ (xᵃ)ᵇ = xᵃᵇ)
=> 2ˣ⁺⁴⁺⁴ = 2⁴ˣ (∵xᵃ * xᵇ = xᵃ⁺ᵇ)
=> 2ˣ⁺⁸ = 2⁴ˣ
//when bases are same powers are equal.
x + 8 = 4x
3x = 8
x = 8/3
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