Question

2 x^4 + 8 x - 3 / 4 - 2 x^2​

Answer 1

$= \frac{2 {x}^{4} + 8x - 3 }{4 - 2 {x}^{2} } \\ = 2 {x}^{4} + 8x - 3 - 4 + 2 {x}^{2} \\ = 2 {x}^{4} + 2 {x}^{2} + 8x - 7 \\ = {2x}^{4 + 2} + 8x - 7 \\ = 2 {x}^{6} + 8x - 7$

am i right ???

Right then plz

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mark as brainliest answer.