Question

2^x × 4^x = 8^1/3 × 32^1/5
Find the value of x.

Answer 1

Hey mate your answer is here......

$= > {2}^{x} \times {4}^{ \frac{1}{3} } = {8}^{ \frac{1}{3} } \times {32}^{ \frac{1}{5} } \\ = > {2}^{x} \times {2}^{ \frac{2}{3} } = {2}^{ \frac{3}{3} } \times {2}^{ \frac{5}{5} } \\ = > {2}^{x + \frac{1}{3} } = 2 \times 2 \\ = > {2}^{x + \frac{1}{3} } = > {2}^{2} \\ \\ comparing \: of \: bases \\ = > x + \frac{1}{3} = 2 \\ = > x = 2 - \frac{1}{3} \\ = > x = \frac{6 - 1}{3} \\ = > x = \frac{5}{3}$
Hope it helps you........

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