2(x-5)=(x-5)(x+3). solve
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first multiply the LHS terms and multiply the (x-5)(x+3)
and then we get 2x-10=xsquare-2x-15
and last we get xsquare-2x-15 =-15+10
xsquare=25
x=5
and then we get 2x-10=xsquare-2x-15
and last we get xsquare-2x-15 =-15+10
xsquare=25
x=5
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