Question

√2^x-7=32 find the value of x​

Answer 1

Answer:

$\sqrt{2} x - 7 = 32 \\ \sqrt{2} x = 32 + 7 \\ \sqrt{2} x = 39 \\ x = \frac{39}{ \sqrt{2} } \\ x = (39 \times \sqrt{2} ) \div (\sqrt{2} \times \sqrt{2} ) \\ x = \frac{39 \sqrt{2} }{2 }$

Answer 2

Answer:

x = 17

Step-by-step explanation:

$(\sqrt{2})^{x-7} = 2^5$

=> $2^{\frac{x-7}{2} } = 2^5$

=>$\frac{x-7}{2} = 5$

=>x - 7 =10

=> x =17

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