2^x-7*5^x-4=1250 find x
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Answered by
4
first of all. Find factor of 1250
1250=2×5×5×5×5
so,
2^(x-7)=2or5^(x-4)=2×5×5×5×5
this is possible only when
2^(x-7)=2or5^(x-4)=4
(x-7)=1 or x-4 = 4
x=8
1250=2×5×5×5×5
so,
2^(x-7)=2or5^(x-4)=2×5×5×5×5
this is possible only when
2^(x-7)=2or5^(x-4)=4
(x-7)=1 or x-4 = 4
x=8
Answered by
0
Correct question:
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Required answer:
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Transposing 7 to the other the other side, we get:
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Therefore, 8 is the required value of x in the given expression.
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