Question

2 x square - 4 x + 8

Answer 1

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Answer 2

Answer:

The roots are $x=1+\sqrt{-3},1-\sqrt{-3}$

Step-by-step explanation:

Given : The quadratic equation - $2x^2-4x+8$

To find : The solution of quadratic equation ?

Solution :  

Using quadratic formula,

General form - $ax^2+bx+c=0$ $D=b^2-4ac$  

Solution is $x=\frac{-b\pm\sqrt{D}}{2a}$  

Equation is $2x^2 -4x+8= 0$

where, a=2 , b=-4, c=8

$D=b^2-4ac$

$D=(-4)^2-4(2)(8)$

$D=16-64$ $D=-48$

Solution is $x=\frac{-b\pm\sqrt{D}}{2a}$

$x=\frac{-(-4)\pm\sqrt{-48}}{2(2)}$  

$x=\frac{4\pm4\sqrt{-3}}{4}$  

$x=\frac{1\pm\sqrt{-3}}{1}$  

Therefore, The roots are $x=1+\sqrt{-3},1-\sqrt{-3}$