Question

2 X square + 4 x minus 8 is equal to zero solve using the method of completing square​

Answer 1

Step-by-step explanation:

$2 {x}^{2} + 4x - 8 = 0 \\ \frac{2 {x}^{2} + 4x - 8}{2} = 0 \\ \frac{2( {x}^{2} + 2x - 4) }{2} = 0 \\ {x}^{2} + 2x - 4 = 0 \\ {x}^{2} + 2x = 4 \\ add \: {1}^{2} on \: both \: sides \\ {x}^{2} + 2x + {1}^{2} = 4 + {1}^{2} \\ {(x + 1)}^{2} = 5 \\ x + 1 = \sqrt{5} \\ x = - \sqrt{5} - 1 \\ x = \sqrt{5} - 1$

Answer 2

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