2 x square-5x upon 6 +1/12
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Step-by-step explanation:
2x²-5x/6+1/12
=> making denominator equal ,
=> (24x²-10x+1)/12
=> taking 1/12 common,
1/12(24x²-10x+1)
using splitting the middle term ,
=> 1/12 (24x²-6x-4x+1)
=> 1/12[6x(4x-1)-1(4x-1)]
=> 1/12[(4x-1)(6x-1)]
=> 1/12(4x-1)(6x-1)
hope this helps
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