Question

2 X square + 6 under root 3 x minus 60 is equal to zero

Answer 1

As the question is
2x^2 +6√3 x -60. = 0
Dividing each term by 2, we will get
x^2 +3√3 x -30 = 0
By applying quadratic formula, you will get
2√3 and -5√3 as zeroes.

Answer 2

Answer:

Roots of given quadratic equation are $x = -5\sqrt{3}\:Or \: x =2\sqrt{3}$

Explanation:

Given quadratic equation:

2x²+6√3x-60=0

Divide each term by 2 ,we get

=> x²+3√3x-30=0

Splitting the middle term,we get

=> x²+5√3x-2√3x-30=0

=> x²+5√3x-2√3x-2√3(5√3)=0

=> x(x+5√3)-2√3(x+5√3)=0

=> (x+5√3)(x-2√3)=0

=> x+5√3=0 Or x-2√3=0

$\implies x = -5\sqrt{3}\: Or\: x =2\sqrt{3}$

Therefore,

Roots of given quadratic equation are $x = -5\sqrt{3}\: Or \:x =2\sqrt{3}$

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