2 X square + kx - 6;x=2. find the value of k
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4
Hey !!
Here is your answer !!
2 × ( x )2 + k × x - 6 =0
2 × (2)2 + 2k - 6 =0
8 +2k -6 = 0
2 +2k = 0
k = -2/2
k = -1
Here is your answer !!
2 × ( x )2 + k × x - 6 =0
2 × (2)2 + 2k - 6 =0
8 +2k -6 = 0
2 +2k = 0
k = -2/2
k = -1
SamratRoy:
thanks you
Answered by
6
Hey user here is ur answer...
![2 {x}^{2} + kx - 6 = 0 \\ by \: putting(x = 2) \\ 2 ({2})^{2} +2k - 6 = 0 \\ 8 - 6 = - 2k \\ 2 = - 2k \\ k = - 1 \\ its \: ur \: answer 2 {x}^{2} + kx - 6 = 0 \\ by \: putting(x = 2) \\ 2 ({2})^{2} +2k - 6 = 0 \\ 8 - 6 = - 2k \\ 2 = - 2k \\ k = - 1 \\ its \: ur \: answer](https://tex.z-dn.net/?f=2+%7Bx%7D%5E%7B2%7D++%2B+kx+-+6+%3D+0+%5C%5C+by+%5C%3A+putting%28x+%3D+2%29+%5C%5C+2+%28%7B2%7D%29%5E%7B2%7D++%2B2k+-+6+%3D+0+%5C%5C+8+-+6+%3D++-+2k+%5C%5C+2+%3D++-+2k+%5C%5C+k+%3D++-+1+%5C%5C+its+%5C%3A+ur+%5C%3A+answer)
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