Question

2 x square minus 5by 6 x +1 by 12

Answer 1

question:

$2 {x}^{2} - 5 \div 6x + 1 \div 12$

answer:

making denominator equal,

$(24 {x}^{2} - 10x + 1)12$

taking 1/12 common,

$1 \div 12(24 {x}^{2} - 10x + 1)$

using spitting the middle term ,

$1 \div 12(24 {x}^{2} - 6x - 4x + 1)$

$1 \div 12{6x(4x - 1) - 1(4x - 1)$

$1 \div 12(4x - 1)(6x - 1)$

$1 \div 12(4x - 1)(6x - 1)$

I hope you understand this sum