2 - x - x^2 >= 0
find the solutions of x
yasummu:
hey i am really sorry i answered it wrong please forgive me i did not observe and understand it
sorry to waste your points
no problem
THANX but your points are wasted right. well it is so kind of you thank you
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x=1 nd x= -2 is correct ans ..
the given question is an inequality not an equation
please dont ans if u dont know
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Given
2 - x - x² = 0
⇒ 0 = x² + x - 2
⇒ x² + x - 2 = 0
⇒ x² + 2x - x - 2 = 0
⇒ x(x + 2) - 1(x + 2) = 0
⇒(x + 2) (x - 1) = 0
⇒ x + 2 = 0 or x-1 = 0
⇒ x = -2 or x= 1
∴ x = -2 , 1
2 - x - x² = 0
⇒ 0 = x² + x - 2
⇒ x² + x - 2 = 0
⇒ x² + 2x - x - 2 = 0
⇒ x(x + 2) - 1(x + 2) = 0
⇒(x + 2) (x - 1) = 0
⇒ x + 2 = 0 or x-1 = 0
⇒ x = -2 or x= 1
∴ x = -2 , 1
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