Question

(2+x)(x-7)/(x-5)(x+4)=1​

Answer 1

$\frac{(2 + x)( \times - 7)}{(x - 5)(x + 4)} = \frac{1}{1} \\ (2 + x)(x - 7) = ( x - 5)(x + 4) \\ 2(x - 7) + x(x - 7) = x( x + 4) - 5(x + 4) \\ 2x - 14 + {x}^{2} - 7x = {x}^{2} + 4x - 5x + 20 \\ - 5x - 14 = - x - 20 \\ - 5x + x = - 20 + 14 \\ - 4x = - 6 \\ x = \frac{3}{2}$

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Answer 2

$\huge\mathbf\red{answer~~↓~↓}$

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To solve :

$\sf \frac{(2 + x)(x - 7)}{(x - 5)(x + 4)} = 1 \\ \\ \sf By \: cross \: multiplication, \: we \: get \\ \\ \sf (2 + x)(x - 7) = (x - 5)(x + 4) \\ \sf 2x - 14 + {x}^{2} - 7x = {x}^{2} + 4x - 5x - 20 \\ \sf {x}^{2} - 5x - 14 = {x }^{2} - x - 20 \\ \sf {x}^{2} - {x}^{2} - 5x + x = - 20 + 14 \\ \sf - 4x = - 6 \\ \sf 4x = 6 \\ \sf x = \frac{6}{4} \\ \\ \sf x = \frac{3}{2}$

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$\huge\mathbf\red{Hope~it~helps..!!}$