2[x]=x+{x} find the value of x ; where [.] is greatest integer function and {.} is fractional part function
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Answer:
-1.5, 0.0
Step-by-step explanation:
Let the number x be divided into two parts.
integer part A, and fractional part b.
hence, X = A.b
case (b is not 0)
since b is not 0, therefore [X]=[A.b]= A+1
and {X}=0.b
then equation stands as
2(A+1)=A.b + 0.b,
2A +2= A + 2(0.b)
A=2(0.b)-2
now A is integer, 2 is also integer. hence, 2(0.b) should also be an integer.
if b is not zero and 0.b<=1, thus, 0.b=1/2=0.5
or, A=2(0.5)-2=-1
this, number is -1.5 (satisfies the equation)
case( b is 0)
since b is 0, [A.b]=A
thus, according to equation, 2A=A+0, which is possible off A=0. thus, the number is 0.0
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