2(x + y)² – 9 (x + y) – 5 =
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Let (x+y)=p, then the equation 2(x+y)^2
−9(x+y)−5 becomes 2p^2
−9p−5
Consider the expression 2p^2
−9p−5 we can factorise it as follows:
2p^2 −9p−5=2p^2
−10p+p−5=2p(p−5)+1(p−5)=(p−5)(2p+1)
Now, substitute the value of p as p=(x+y):
(p−5)(2p+1)=(x+y−5)(2(x+y)+1)=(x+y−5)(2x+2y+1)
Hence, 2(x+y)^2
−9(x+y)−5=(x+y−5)(2x+2y+1)
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