Question

(2^x+y,2^x-y)= (16,1)
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Answer 1

Answer:

x=2 and y=2

Step-by-step explanation:

2^x+y=16     2^x+y=2^4

x+y=4

2^x-y=1     2^x-y=2^0

x-y=0    x=y

Substitution method we get x=2 and y=2

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