Question

2^x+y=2^x-y=√32,then find x and y.​

Answer 1

Answer:

x = 5/2, y=0

Step-by-step explanation:

Let 2^x be a

Then

a+y = √32

a-y = √32

Solving both the equations

2a = 2√32

a = √32

2^x = 2^ (5/2)

x = 5/2

Putting the value of a in first eqn, we get

y = 0