Question

2^x+y=2^x-y=√8 solve it.

Answer 1

HEY MATE HERE IS YOUR ANSWER

2(x + y) = \sqrt{8} \\ 2x + 2y = 2 \sqrt{2} = = = > (1)eq

2(x - y) = \sqrt{8} \\ 2x - 2y = 2 \sqrt{2} = = = > (2)eq

by adding 1 eq and 2 eq

2x + 2y + 2x - 2y= 2 \sqrt{2} + 2 \sqrt{2} \\ 4x = 4 \sqrt{2} \\ x = \sqrt{2}

substitute the value of x in 1 or 2 eq

2( \sqrt{2} ) + 2y = 2 \sqrt{2} \\ 2y = 2 \sqrt{2} - 2 \sqrt{2} \\ y = 0

HOPE IT HELPS YOU