Question

2. x,y are the zeros of the polynomial f(x) = 4x + 3x + 7, then 1/x+1/y​

Answer 1

Answer:

Step-by-step explanation:

1/x + 1/y

taking lcm we get

(x+y)/xy

we know that sum of zeroes of polynomial ax2 + bx + c = 0

is -b/a

and product is c/a

answer = -b/c = -3/4

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Answer 2

$\huge{\bigstar}{ \green{ \mathfrak{ \underline{ \underline{Question}}}}}{\bigstar}$

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$If\: x,\:y \: are\: the\: zeros \:of \:the\: polynomial \\ f(x) = 4x + 3x + 7, \:then \:find\: \displaystyle{\frac{1}{x}}+\displaystyle{\frac{1}{y}}$

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$\huge{\bigstar}{ \green{ \mathfrak{ \underline{ \underline{Answer}}}}}{\bigstar}$

$\boxed{\red{\bold{Sum\: of \: zeroes:}}}$

$\purple{\implies x + y = \displaystyle{\frac{-b}{a}}}$

$\purple{\implies}x + y= \displaystyle{\frac{-3}{4}}$

$\boxed{\red{\bold{Product \: of \: zeroes:}}}$

${\purple{\implies xy= \displaystyle{\frac{c}{a}}}}$

${\purple{\implies}}xy = \displaystyle{\frac{7}{4}}$

$\boxed{\red{\bold{Simplyfing \:expression:}}}$

$\green{\implies \displaystyle{\frac{1}{x}} + {\frac{1}{y}}}$

$\green{\implies}\displaystyle{\frac{x+y}{xy}}$

$\green{\implies}\displaystyle{\frac{-3}{4}} ÷ \frac{7}{4}$

$\green{\implies \boxed{\bold{\displaystyle{\frac{-3}{7}}}}}$

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