Math, asked by aditya8360, 1 year ago

2×(x²+1)=5x solve quadratic equation


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Answers

Answered by shubhamkumar81
11
2x²+2=5x
2x²-5x+2=0
2x²-4x-x+2=0
2x(x-2)-1(x-2)
(2x-1)(x-2)
Answered by iHelper
21
Hello!

\bf{2 ( x^{2} + 1 ) = 5x}

⇒ 2x² + 2 = 5x

⇒ 2x² - 5x + 2 = 0

\underline{\sf Now} :

⇒ 2x² - 4x - x + 2 = 0

⇒ 2x ( x - 2 ) - 1 ( x - 2 ) = 0

\boxed{\sf ( x - 2 ) ( 2x - 1 ) = \sf 0}

Hence,
The required solⁿ is \bf{x = 2} Or \bf{x = \dfrac{\sf 1}{\sf 2}}

Cheers!
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