Question

2^x2 +2^x =16, find the
value of x² ,​

Answer 1

Answer:

phale follow fir such ma answer dunga

Answer 2

$2^x^2 +2^x =16$

$x^2$log2 + xlog2 = log16

log2($x^2$ + x) = log16

0.3($x^2$ + x) = 1.2

$x^2$ + x = 4

$x^2$ + x - 4 = 0

$ax^2 + bx + c = 0$

x = (-b +or- $b^2$ - 4ac)/2a

x = (-1 +or- 1*1 - 4*1*-4)/2*1

x = 0.6 or -1.6

$x^2$ = 0.36 or 2.56

:-)