Question

2(x²-2) (x²+7)


Solve please!!!

Answer 1

Answer:

Step-by-step explanation:

Hey,

(x+2)^2 =(x-5)^2+7,how do I solve for x?

At first here we have to use the formulas (a+b)^2 and (a-b)^2 for solving (x+2)^2 and (x-5)^2 …we know (a+b)^2= a^2+2ab+b^2 and

(a-b)^2= a^2–2ab+b^2

So using these formulas solve for (x+2)^2 and (x-5)^2

(x+2)^2= x^2+4x+4

(x-5)^2=x^2–10x+25

So solve the equation

(x+2)^2=(x-5)^2+7

=>x^2+4x+4=x^2–10x+25+7

=>4x+4=32–10x

=>4x+10x=32–4

=>14x=28

=>x=28/14

=>x=2

If you want to check if your answer is correct or not then you can put the value of x in the equation.

So putting the value of x in the equation we get

(2+2)^2=(2–5)^2+7

=>4^2=(—3)^2+7

=>16=16

Thus,our value of x is correct

So the value of x =2

I hope you may get some help..

Thank you