2/x2-5/x +2=0,x not equal to 0
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Answered by
2
Step-by-step explanation:
let 1/x be y..
then, 2y^2 - 5y + 2 = 0
or 2y^2 - 4y - y + 2 =0
2y(y-2) - 1(y-2) = 0
(y-2)(2y-1) = 0
so y is either 2 or 1/2
but x is 1/y, hence x is 1/2 or 2
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