Question

2/x²-5/x+2=0(x not equal to 0)​​

Answer 1

Answer:

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Answer 2

$\frac{2}{ {x}^{2} } - \frac{5}{x} + 2 = 0 \\ \\ \longrightarrow \: {x}^{2} \bigg( \frac{2}{ {x}^{2} } - \frac{5}{x} + 2 \bigg) = 0 \\ \\ \longrightarrow \: 2 {x}^{2} - 5x + 2 = 0 \\ \\ \longrightarrow \: 2 {x}^{2} - 4x - x + 2 = 0 \\ \\ \longrightarrow \: 2x \bigg( x - 2 \bigg) - \bigg(x - 2 \bigg) = 0 \\ \\ \longrightarrow \bigg(x - 2 \bigg) \bigg(2x - 1 \bigg) = 0 \\ \\ \large{ \therefore} \: \: \: \: \: \boxed{\begin{array}{c|c} \longrightarrow \bf \: x = 2 \: \: \: \: \: \: \: \: \: & \longrightarrow \bf x = - \frac{1}{2} \end{array}}$