√2 x²- 7/2 x4+ x-5 x³. Rewrite the polynomial in standard form.
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Answered by
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standard form of the polynomial
√2x^2 - 7/2 x^4 + x - 5x^3
= - 7/2 x^4 - 5x^3 + √2x^2 + x
√2x^2 - 7/2 x^4 + x - 5x^3
= - 7/2 x^4 - 5x^3 + √2x^2 + x
Answered by
1
Hi ,
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We know the standard form of
4th degree polynomial ,
ax⁴ + bx³ + cx² + dx + e ,
where a ≠ 0 ,
a , b , c , d ,e are real numbers.
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Now ,
Given polynomial is
√2x² - (7/2)x⁴ + x - 5x³
Rewriting the polynomial in
standard form we get,
(-7/2)x⁴ - 5x³ + √2x² + x + 0
a =-7/2 ,b = -5 ,c = √2 ,d = 1 ,e = 0
I hope this helps you.
: )
*****************************************
We know the standard form of
4th degree polynomial ,
ax⁴ + bx³ + cx² + dx + e ,
where a ≠ 0 ,
a , b , c , d ,e are real numbers.
****************************************
Now ,
Given polynomial is
√2x² - (7/2)x⁴ + x - 5x³
Rewriting the polynomial in
standard form we get,
(-7/2)x⁴ - 5x³ + √2x² + x + 0
a =-7/2 ,b = -5 ,c = √2 ,d = 1 ,e = 0
I hope this helps you.
: )
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