Question

2×xsquare(1+undroot2)
where x is equals to 8​

Answer 1

Answer:

x 2 +x−(a+2)(a+1)=0 are (a+1) and −(a+2)

Answered By

Step-by-step explanation:

Given x  

2

+x−(a+2)(a+1)=0, Here, a = 1, b = 1, c = -(a + 2)(a + 1)

x=  

2a

−b±  

b  

2

−4ac

​  

 

​  

=  

2(1)

−1±  

1  

2

−4{(a+2)(a+1)}

​  

 

​  

=  

2

−1±  

1−4{−(a  

2

+3a+2)

​  

 

​  

 

x=  

2

−1±  

1+4a  

2

+12a+8

​  

 

​  

=  

2

−1±  

4a  

2

+12a+9

​  

 

​  

=  

2

−1±  

(2a+3)  

2

 

​  

 

​  

= −1±(2a+3)

​  

 

∴x=  

2 −1+2a+3

and x=  

2 −1−2a−3

​  

∴x=  2  

2a+2

​  

 and x= 2−2a−4 x=a+1x=−(a+2)