Question

2 xsquare +3x+k=0. find the value of k whose roots are real and equal​

Answer 1

Hey mate here's your answer:-

2x^2+3x+k=0

for equal roots:-

D=0

D=b^2-4ac

therefore:-

a=2,b=3,c=k

(3)^2-4*2*k=0

9-8k=0

8k=9

k=9/8(ANSWER)

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Answer 2

Answer:

Bsquare-4ac=0

3square-4×2×k=0

9-8k=0

So k is 9/8

Step-by-step explanation: