Question

(2 + xy) (3 - xy) using property (x + a) (x -b) = x(the power 2) +(a-b)x - ab

Answer 1

(2+xy) (3-xy) = xy(3+2)xy+3*2
=xy*5xy+6
=
$5x {}^{2}y + 6$

Answer 2

Answer:

(x+a)(x-b)=x^2 + (a-b)x - ab.

since, both x should be same (according to property)

we can rewrite the question as ----

(2+xy)(3-xy) = [2+xy][2-(xy-1)]

now we can apply the property given i.e.

(x+a)(x-b)=x^2 + (a-b)x - ab ------> 1

[2+xy][2-(xy-1)] -------->2

comparing the equations we get

x=2; a=xy ;b=xy-1

applying the property we get,[(x+a)(x-b)=x^2 + (a-b)x - ab]

[2+xy][2-(xy-1)] = (2)^2 +[xy-(xy-1]2 -xy(xy-1)

                       =4 +[xy- xy +1]2 - (xy)^2 +xy

                       =4 + 0 +2 - (xy)^2 +xy

                       =6 -(xy)^2 + xy -------> final answer

Notation:

(xy)^2 indicates xy(the power 2)

and

(2)^2 indicates 2(the power 2)