Math, asked by ksingh69983, 5 months ago

2
xy, -7y, 3xy?, - xyz, x2​

Answers

Answered by SAKSHITHELEARNER26
0

Answer:

left(-x+y-z\right)\times-2x

=-x-2x+y-2x-z-2x

=2x^2-2xy+2xz

(ii) xy-yz\times x^2yz^2

=xy.x^2yz^2-yz.x^2yz^2

=x^{2+1}\times y^{1+1}\times x^2-x^2\times y^{1+1}\times z^{2+1}

=x^3y^2z^2-x^2y^2z^3

(iii) 2xyz+3xy\times-2y^2z

=2xyz-2y^2z+3xy-2y^2z

=-4x\times y^{2+1}\times z^{1+1}-6\times x\times y^{2+1}\times z

=-4xy^3z^2-6xy^3z

(iv) -3xy^2+4x^2y\times-xy

=-3xy^2-xy+4x^2y-xy

=3x^2y^3-4x^3y^2

(v) -x^2y-3x^2y^2\times4xy

=-x^2y.4xy-3x^2y^2.4xy

=-4x^3y^2-12x^3y^3

Answered by jaithra2007
0

Answer:

Step-by-step explanation:

i dint understood so resend what u want to tell

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