Question

2. XY is a diameter of a circle, PAQ is a tangent to the circle at the point. 'A' lying on the
circumference. The perpendicular drawn on the tangent of the circle from X intersects
PAQ at Z. Let us prove that XY is a bisector of YXZ.

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Answer 1

Answer:

Step-by-step explanation:

Angle XAY =90∘

And XA = AY

Thus < AXY = AYX

In△ AXY,

<AXY+<AYX+<XAY = 180∘(As sum of angles of a triangle =180∘

Thus,

2<AXY=90∘(<AXY<AYX and <XAY=90∘)

<AXY=45∘

<ZXY=90∘

Thus, <AXZ=45∘

Hence, XA bisects <YXZ