Question

х/2+y=0.8;7/x+y/2=10​

Answer 1

Answer:

$\frac{x}{2} + y = \frac{8}{10} \: \: \: \: \: \: (1) \\ \frac{7}{x} + \frac{y}{2} = 10 \: \: \: \: \: (2) \\ = > \frac{x + 2y}{2} = \frac{8}{10} \\ = > x + 2y = \frac{8}{5} = 1.6 \: \: \: (3) \\ = > \frac{14 + xy}{2x} = 10 \\ = > 14 + xy = 20x \\ = > 14 = 20x - xy \\ = > 14 = x(20 - y) \\ = > x = \frac{14}{20 - y} \\ substituting \: the \: value \: of \: x \: in(3) \\ \frac{14}{20 - y} + 2y = 1.6 \\ = > 14 + 40y - 2 {y}^{2} = 1.6 \\ = > 2 {y}^{2} - 40y - 12.4 = 0 \\ = > {y}^{2} - 20y - 6.2 = 0$

Answer 2

Step-by-step explanation:

the upper answer it is correct plz mark it as brainlist