Question

2(y+1)^2-5(y+2)=12 find the value of y​

Answer 1

Answer:

2(y^2+2y+1)-5y-10=12

2y^2+4y+2-5y-10=12

2y^2-y-8=12

2y^2-y-20=0

Answer 2

I hope this answer help you