Math, asked by puspalatasahoo207, 6 months ago

2(y-2)+3(4y-1) equal to 0​

Answers

Answered by Anonymous
14

Answer:

2(y - 2) + 3(4y - 1) = 0 \\ 2y - 4 + 12y - 3 = 0 \\ 12y + 2y - 4 - 3 = 0 \\ 14y - 7 = 0 \\ 14y = 0  + 7 \\ 14y = 7 \\ y =  \frac{7}{14}  =  \frac{1}{2}  = 0.5

The value of y is (0.5).

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Answered by payalkarn
7

Answer:

y = 1/2

Step-by-step explanation:

2(y-2)+3(4y-1)=0

2y-4+12y-3 =0

12y+2y-4-3 =0

14y - 7 =0

14y = 0+7

14y= 7

y = 7/14

y =1/2

y = 0.5

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