Math, asked by arjithpillai, 1 day ago

(2−y)^3=
please do it​

Answers

Answered by riya029
2

Step-by-step explanation:

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Answered by IIMrVelvetII
36

Answer: 8 - y³ + 6y² - 12y

Step-by-step explanation:

By using identity (a - b)³ = a³ - b³ - 3ab(a - b)

Here, a = 2 and b = y

Putting the giving values in the identity, we get,

\sf→{2}^{3} - {y}^{3} - 3(2 \times y)(2 - y)

\sf→8 - {y}^{3} - 6y(2 - y)

\sf→8 -  {y}^{3} - 12y - 6{y}^{2}

❍ Rearranging terms,

\sf→8 -  {y}^{3} + {6y}^{2} - 12y

Hence (2-y)³ is equal to 8 - y³ + 6y² - 12y.

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