Question

2 y square + 27y + 13 is equal to zero solve the following quadratic equation by factorisation

Answer 1

Hey here is your answer ☺️

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2y2 + 27y + 13 = 0

2y2 + 26y + y + 13 = 0

2y(y + 13) + 1(y + 13) = 0

= (2y + 1)( y + 13)

either , (2y + 1) = 0

2y = -1

y = -1/2

or ,

(y + 13) = 0

y = - 13


I HOPE IT WILL HELP YOU ☺️


Thanx for asking ur question ✌️✌️

Answer 2

Hi friend
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Your answer
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★ FACTORISATION
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2y² + 27y + 13 = 0

=> 2y² + 26y + y + 13 = 0

=> 2y(y + 13) + 1(y + 13) = 0

=> (y + 13)(2y + 1) = 0

Now,
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y + 13 = 0

=> y = - 13

Again,
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2y + 1 = 0

=> 2y = - 1

=> y = - 1/2

Therefore ,
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y = - 13 OR y = - 1/2

HOPE IT HELPS