Question

2) y2-12y+36 by splitting the middle term​

Answer 1

Step-by-step explanation:

y^2-12y+36

=y^2-6y-6y+36

=y(y-6)-6(y-6)

=(y-6)(y-6)

Answer 2

Question:-

Factorise

${y}^{2} - 12y + 36$

Solution:-

36 can be written as -6 × -6

So, -12 = -6 +(-6)

${y}^{2} - 6y - 6y + 36$

$y(y - 6) - 6(y - 6)$

$(y - 6)(y - 6)$

$y - 6 = 0 \: \: \: \: \: and \: \: \: y - 6 = 0$

$y = 6 \: \: \: \: and \: \: \: \: y = 6$