2 year ago a father was five times as old as his son to you later his age will be eight years more than three times the age of his son find the present age of father and son
Answers
Let us assume the father age to be a and that of son to be b.
ATQ,
a-2=5(b-2).........(1)
a+8=3(b+8).......(2)
On further solving (1) ,
_a-2=5b-10
a=5b-10+2
a=5b-8.........(3)
On solving (2) ,
__a+8=3b+24
Substituting from (3),
(5b-8)+8=3b+24
2b=24
b=12......(4)
Putting value of b in (3)
a=5b-8
=60-8
=52
Therefore age of father is 52 years and age on son is 12 years.
Let us assume the father age to be a and that of son to be b.
ATQ,
a-2=5(b-2).........(1)
a+8=3(b+8).......(2)
On further solving (1) ,
_a-2=5b-10
a=5b-10+2
a=5b-8.........(3)
On solving (2) ,
__a+8=3b+24
Substituting from (3),
(5b-8)+8=3b+24
2b=24
b=12......(4)
Putting value of b in (3)
a=5b-8
=60-8
=52
Therefore age of father is 52 years and age on son is 12 years.
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