Question

2 year ago, A man was 5 time as old as his son 2year later his age was be 8more than 3 time age of son​

Answer 1

Step-by-step explanation:

Let the age of a man = x years

And the age of his son = y years

Two years ago,

Man’s age = (x – 2) years

Son’s age = (y – 2) years

According to the question,

(x – 2) = 5(y – 2)

⇒ x – 2 = 5y – 10

⇒ x = 5y – 10 + 2

⇒ x = 5y – 8 ...(i)

Two years later,

Father’s age = (x + 2) years

Son’s age = (y + 2) years

According to the question,

(x + 2) = 8 + 3(y + 2)

⇒ x + 2 = 8 + 3y + 6

⇒ x = 3y + 12 …(ii)

From Eq. (i) and (ii), we get

5y – 8 = 3y + 12

⇒ 5y – 3y = 12 + 8

⇒ 2y = 20

⇒ y = 10

On putting the value of y = 11 in Eq. (i), we get

x = 5(10) – 8

⇒ x = 50 – 8

⇒ x = 42

Hence, the age of man is 42 years and the age of his son is 10 years.

Answer 2

Answer:

age of men = 42 years

or age if son = 10 years

Step-by-step explanation:

let the men age = x

and his son ags = y

two year ago,

(x - 2) = 5(y - 2)

x - 2 = 5y - 10

x - 5y = - 10 + 2

x - 5y = -8 ----------------(1)

2 year later,

(x + 2) = 3(y + 2) + 8

x + 2 = 3y + 6 + 8

x - 3y = 14 - 2

x - 3y = 12 -----------(2)

on subtract eq 1 and 2

x - 5y = -8

x - 3y = 12

- + -

-2y = -20

2y = 20

y = 20/2

y = 10

put y in eq 1

x - 5y = -8

x - 5(10) = -8

x - 50 = -8

x = -8 + 50

x = 42

age of men = 42

age of his son = 10