2 years
1201
O No 11 Calculate the amount when P= 1000, R = 10% per annum (compounded annually) Time
Answers
Answered by
19
Answer:
Here, Principal P = Rs. 1000
R =10% per annum and n=2 years
∴ Amount after 2 years =
p(1 + \frac{r}{200} ) ^{2n}p(1+
200
r
)
2n
= 1000 \times (1 + \frac{10}{200} ) {}^{2 \times 2}=1000×(1+
200
10
)
2×2
= 1000 \times (1 + \frac{1}{20} ) {}^{4}=1000×(1+
20
1
)
4
= 1000 \times ( \frac{21}{20}) {}^{4}=1000×(
20
21
)
4
= 1000 \times \frac{21}{20} \times \frac{21}{20} \times \frac{21}{20} \times \frac{21}{20}=1000×
20
21
×
20
21
×
20
21
×
20
21
= 1215.50=1215.50
Hence, compound interest = Amount - Principal
= 1215.50 - 1000=1215.50−1000
= 215.50=215.50
Answered by
1
Answer:
p= 1000
R = 10%
T = 1 year
Step-by-step explanation:
P× R× T/100
= 1000× 10 × 1 / 100= 100= simple interest
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