Question

2 years ago, a father was 5 times as old as his son. 2 years later, his age will be 8 more than 3 times the age of the son.find the present age of father and son.

Answer 1

Answer:

let the son be x.

5x+2=8x+3+2

2+1=3x

3=3x

1=x

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Answer 2

Step-by-step explanation:

Let the son's age two year ago be x.

Then father's will be 5x.

2 years later,

father age = 5x + 2

son's age = x+2

According to question,

5x + 2 = 3(x+2) + 8

5x = 3x + 6 + 8 - 2

2x = 12

x = 6

Now this age is of two years ago,

So present age of son = x+2 = 8

present age of father = 5x + 2 = 32

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