2 years ago a father was 5 times as old as his son 2 years later his age will be 8 more than 3 times the age of the Son find the present age of father and son
Answers
Answered by
7
Hi there !!
Here's your answer
Let the son's age 2 years ago be x years
Father's age 2 years ago = 5x years
Present ages of :
Son = x + 2 years
Father = 5x + 2 years
Ages of father and son 2 years later:
Son = x + 2 + x = x + 4 years
Father = 5x + 2 + 2 = 5x + 4 years
Given,
2 years later fathers age will be 8 more than 3 times the age of the Son
So,
the following balanced equation will be formed
3(x + 4) + 8 = (5x + 4)
3x + 12 + 8 = 5x + 4
3x + 20 = 5x + 4
20 - 4 = 5x - 3x
16 = 2x
x = 8
So,
Present age of son = x + 2 = 8 + 2 = 10 years
Present age of father = 5x + 2 = 5(8)+2 = 42 years
Thus,
the present ages of father and son are 42 years and 10 years respectively
________________________________
Hope it helps !!
Here's your answer
Let the son's age 2 years ago be x years
Father's age 2 years ago = 5x years
Present ages of :
Son = x + 2 years
Father = 5x + 2 years
Ages of father and son 2 years later:
Son = x + 2 + x = x + 4 years
Father = 5x + 2 + 2 = 5x + 4 years
Given,
2 years later fathers age will be 8 more than 3 times the age of the Son
So,
the following balanced equation will be formed
3(x + 4) + 8 = (5x + 4)
3x + 12 + 8 = 5x + 4
3x + 20 = 5x + 4
20 - 4 = 5x - 3x
16 = 2x
x = 8
So,
Present age of son = x + 2 = 8 + 2 = 10 years
Present age of father = 5x + 2 = 5(8)+2 = 42 years
Thus,
the present ages of father and son are 42 years and 10 years respectively
________________________________
Hope it helps !!
Anonymous:
:-)
Answered by
3
Hi there!
Let the age of father is x years and that of son is y years.
ATQ,
x - 2 = 5(y-2)
⇒x - 5y = -10+2
⇒ x - 5y = -8
⇒ x = 5y-8
x+2 = 3(y+2)+8
⇒ x - 3y = 6 + 8 - 2
⇒ 5y - 8 - 3y = 12
⇒ 2y = 12 + 8
⇒ y = 20/2
⇒ y= 10
So,
x = 5y - 8 = 50 - 8 = 42
Therefore,
The age of father is = x = 42 yrs.
The age of son is = y =10 yrs.
[ Thank you! for asking the question. ]
Hope it helps
Let the age of father is x years and that of son is y years.
ATQ,
x - 2 = 5(y-2)
⇒x - 5y = -10+2
⇒ x - 5y = -8
⇒ x = 5y-8
x+2 = 3(y+2)+8
⇒ x - 3y = 6 + 8 - 2
⇒ 5y - 8 - 3y = 12
⇒ 2y = 12 + 8
⇒ y = 20/2
⇒ y= 10
So,
x = 5y - 8 = 50 - 8 = 42
Therefore,
The age of father is = x = 42 yrs.
The age of son is = y =10 yrs.
[ Thank you! for asking the question. ]
Hope it helps
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