Question

2 years ago, a father was 5 times old as his son. 2 years later, his age will be 8 years more than three times the age of the son . find the present ages of father and son

Answer 1

Answer:

Step-by-step explanation:

Let the age of father is x years and that of son is y years.

Then by the given question,

x-2=5(y-2)

or, x-5y=-10+2

or, x-5y=-8

or, x=5y-8

x+2=3(y+2)+8

or, x-3y=6+8-2

or, 5y-8-3y=12

or, 2y=12+8

or, y=20/2

or, y=10

then x=5y-8=50-8=42

Then, the age of father is 42 yrs. and the age of son is 10 yrs.