2 years ago a man's age was three times the square of his daughters age . 3 years hence this age will be 4 times his daughters age. find their present ages.
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let the man age be x
3x - 2 = y*y
3 + x = 4y
from equation 1
x = y*y /3+ 2/3
3 + y *y /3 + 2/3 = 4y
by taking l c m
9/3+y*y/3+2/3=4y
9 + Y square + 2 equals to 12y
11+y*y = 12 y
y*y + 12y +11 =0
y*y + 11 y + y + 11 =0
y (y + 11 ) +1(y+11) =0
(y+11)( y+ 1)=0
y + 11 = -y -1
2y =-12
y = -6
3 + x = -6 *4
x =-24-3=-27
3x - 2 = y*y
3 + x = 4y
from equation 1
x = y*y /3+ 2/3
3 + y *y /3 + 2/3 = 4y
by taking l c m
9/3+y*y/3+2/3=4y
9 + Y square + 2 equals to 12y
11+y*y = 12 y
y*y + 12y +11 =0
y*y + 11 y + y + 11 =0
y (y + 11 ) +1(y+11) =0
(y+11)( y+ 1)=0
y + 11 = -y -1
2y =-12
y = -6
3 + x = -6 *4
x =-24-3=-27
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