Question

2 years ago, dileep was three time as older as his son and two years Hence, twice as his age will equal to five time that of his son. find the president ages.
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Answer 1

Answer:

Step-by-step explanation:

2 years ago,

Son's age = x

Dilip's age = 3x

Present age of Son = x+2

Present age of Dilip = 3x+2

After 2 years,

Son's age = x+2+2 = x+4

Dilip's age = 3x+2+2 = 3x+4

A/Q 2(3x+4) = 5(x+4)

6x+8 = 5x+20

x = 12

∴ Present age of son = x+2 = 12+2 = 14

Present age of Dilip = 3x+2 = 3x12+2 = 38

Answer 2

Given :

• 2 years ago, Dileep was 3 times as old as his son.
• 2 years hence , twice of his age will equal to 5 times of his son.

To find :

• Their present ages.

Solution :

Consider,

• Present age of Dileep = x years
• Present age of his son = y years

According to the 1st condition :-

• 2 years ago, Dileep was 3 times as old as his son.

2 years ago,

• Age of Dileep = (x-2) years
• Age of his son = (y-2) years

➪ x-2 = 3(y-2)

➪ x - 2 = 3y -6

➪ x = 3y-6+2

➪ x = 3y -4......................(i)

According to the 2nd condition :-

• 2 years hence , twice of his age will equal to 5 times of his son.

After 2 years,

• Age of Dileep = (x+2) years
• Age of his son = (y+2) years

➪ 2(x+2) = 5(y+2)

➪ 2x + 4 = 5y +10

➪ 2(3y-4)+4 = 5y +10 [ put x=3y-4]

➪6y - 8 +4 = 5y +10

➪ 6y -5y = 10 +8 -4

➪ y = 14

• Present age of his son = 14 years

Now , put y = 14 in eq(1) for getting the value of x.

➪ x = 3y - 4

➪ x = 3×14 -4

➪ x = 42 - 4

➪ x = 38

• Present age of Dileep = 38 years.