Question

2 years ago Dileep was three times as old as his son and two years hence twice his age will be equal to five times that of his son find their present ages

Answer 1

dillep was 28yrs old

Answer 2

☆ Question ☆

Two years ago Dileep was three times as old as his son and two years hence twice his age will be equal to five times that of his son. Find their present ages.

☆ Given ☆

• 2 years ago, Dileep was 3 times as old as his son.
• 2 years hence , twice of his age will equal to 5 times of his son.

☆ To find ☆

• Their present ages.

☆ Step-by-Step-Explaination ☆

Let Dileep's son's age 2 years ago = x years

Then, Dileep's age 2 years ago = 3x years

Therefore,

Dileep's present age = ( 3x + 2 ) years

Son's present age = ( x + 2 ) years

After 2 years from now, son's age = ( x + 4 ) years

and Dileep's age = ( 3x + 4 ) years

According to the question,

2 ( 3x + 4 ) = 5 ( x + 4 )

=> 6x + 8 = 5x + 20

=> 6x - 5x = 20 - 8

i.e., x = 12

So, Dileep's son's present age = 12 + 2 = 14 years

And Dileep's present age = ( 3 × 12 + 2 ) = 38 years

☆ Check : 2 years ago, ☆

Age of the son = ( 14 - 2 ) years = 12 years

Age of the Dileep = ( 38 - 2) = 36 years

And, 36 = 3 × 12 ( First condition )

☆ 2 years hence, ☆

Age of the son = ( 14 + 2 ) years = 16 years

Age of Dileep = 38 + 2 = 40 years

And, 2 × 40 = 5 × 16 ( Second condition)

80 = 80