Question

2 years ago Dilip was three times as old as his son and 2 years hence twice his age will be equal to 5 times that of his son find their present ages check your solution

Answer 1

Let the present age of Dilip's son be x.
Age of Dilip's son 2 years ago = (x - 2)
Age of Dilip 2 years ago = 3(x - 2)

Age of Dilip's son after 2 years = (x + 2)
Age of Dilip after 2 years = 3(x - 2) + 4 = 3x - 6 + 4 = (3x - 2)

Twice the age of Dilip is equal to five times the age of his son.
2(3x - 2) = 5(x + 2)
6x - 4 = 5x + 10
6x - 5x = 10 + 4
x = 14
Present age of Dilip's son is 14 years.
Age of Dilip 2 years ago = 3(14 - 2) = 36 years
Present age of Dilip = 36 + 2 = 38 years.

Answer 2

Given :-

→ Let Dilip's son's age 2 years ago be x years.

Then, Dilip's age 2 years ago = ( 3x ) years

Thus , the son's age 2 years hence (x + 4) years.

Dilip's age 2 years hence (3x + 4) years.

→ 2 ( 3x + 4 ) = 5 ( x + 4 )

→ 6x + 8 = 5x +20

→ x = 12.

∴ Dilip's son's age 2 years ago = 12 years and Dilip's age 2 years ago = 36 years.

∴ son's present age = 14 years, and

Dilip's present age = 38 years.

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